使用WPF寫一個井字小遊戲演算法
井字遊戲演算法(3*3)
如何判斷 某一條已經連成一直線
最簡單的方法
達成直線總共會有 8 種
橫線 3 條
直線 3 條
斜的 2 條
以此類推
5*5 跟 7*7 的斜線 也是兩條 !!!!
圈圈 跟 叉叉 有兩個 State 我們可以分別給 正跟負的數值作為Flag來定義它的State
其中一方達到直線就遊戲結束
我們可以使用陣列來存取這些 State
Sum[9] 存取 0~8 這些按鈕狀態結果
新增好一個WPF專案後
拉一個Button
去右側屬性區塊更改寬、高
版面設定(Layout) --> Width 跟 Height 皆設定為 100
一般(Common) --> Content 設為 1
Copy Paste 額外的 八個
完成後的最原始 程式碼
MainWindow.xaml.cs 版本1
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
namespace KinectV2_funnyApp
{
///
/// Interaction logic for MainWindow.xaml
///
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
int[] Sum = new int[9];//0~8
//我們用Sum[1]~Sum[8]來對應連為一直線的累計數值狀態
int[] ButtonState = new int[10];
//ButtonState[1]~ButtonState[9]
private void b1_Click(object sender, RoutedEventArgs e)
{
ButtonState[1] = 1;
CheckSum();
}
private void b2_Click(object sender, RoutedEventArgs e)
{
ButtonState[2] = 1;
CheckSum();
}
private void b3_Click(object sender, RoutedEventArgs e)
{
ButtonState[3] = 1;
CheckSum();
}
private void b4_Click(object sender, RoutedEventArgs e)
{
ButtonState[4] = 1;
CheckSum();
}
private void b5_Click(object sender, RoutedEventArgs e)
{
ButtonState[5] = 1;
CheckSum();
}
private void b6_Click(object sender, RoutedEventArgs e)
{
ButtonState[6] = 1;
CheckSum();
}
private void b7_Click(object sender, RoutedEventArgs e)
{
ButtonState[7] = 1;
CheckSum();
}
private void b8_Click(object sender, RoutedEventArgs e)
{
ButtonState[8] = 1;
CheckSum();
}
private void b9_Click(object sender, RoutedEventArgs e)
{
ButtonState[9] = 1;
CheckSum();
}
private void CheckSum()
{
Sum[1] = ButtonState[1] + ButtonState[2] + ButtonState[3];
Sum[2] = ButtonState[4] + ButtonState[5] + ButtonState[6];
Sum[3] = ButtonState[7] + ButtonState[8] + ButtonState[9];
Sum[4] = ButtonState[1] + ButtonState[4] + ButtonState[7];
Sum[5] = ButtonState[2] + ButtonState[5] + ButtonState[8];
Sum[6] = ButtonState[3] + ButtonState[6] + ButtonState[9];
Sum[7] = ButtonState[1] + ButtonState[5] + ButtonState[9];
Sum[8] = ButtonState[3] + ButtonState[5] + ButtonState[7];
if (Sum.Contains(3) == true)
MessageBox.Show("OK");
}
}
}
不過你會發現重複好多程式碼
我們其實可以縮短程式碼
讓同一種功能的只用一段程式進行
所以我們把程式全砍只留下 Button1 的事件即可
MainWindow.xaml.cs 版本2
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
namespace KinectV2_funnyApp
{
///
/// Interaction logic for MainWindow.xaml
///
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
int[] Sum = new int[9];//0~8
//我們用Sum[1]~Sum[8]來對應連為一直線的累計數值狀態
int[] ButtonState = new int[10];
//ButtonState[1]~ButtonState[9]
private void b1_Click(object sender, RoutedEventArgs e)
{
ButtonState[1] = 1;
CheckSum();
}
private void CheckSum()
{
Sum[1] = ButtonState[1] + ButtonState[2] + ButtonState[3];
Sum[2] = ButtonState[4] + ButtonState[5] + ButtonState[6];
Sum[3] = ButtonState[7] + ButtonState[8] + ButtonState[9];
Sum[4] = ButtonState[1] + ButtonState[4] + ButtonState[7];
Sum[5] = ButtonState[2] + ButtonState[5] + ButtonState[8];
Sum[6] = ButtonState[3] + ButtonState[6] + ButtonState[9];
Sum[7] = ButtonState[1] + ButtonState[5] + ButtonState[9];
Sum[8] = ButtonState[3] + ButtonState[5] + ButtonState[7];
if (Sum.Contains(3) == true)
MessageBox.Show("OK");
}
}
}
之後我們到
MainWindow.xaml
但是目前程式執行後不管你按下哪個都只會針對 編號為1的按鈕進行狀態切換
因此我們到右側屬性去搜尋 Uid 更改每一個Button的ID屬性內容
可以作為辨別按鈕的依據
改完後的
MainWindow.xaml
之後我們再回到
MainWindow.xaml.cs
寫 按下去之後取得對應的 Uid 及更改按鈕上面數值為 圈圈 符號的程式
效果呈現
接著就到了探討 是自己 還是 對手 的回合
判斷
我們可以使用 boolean 去做切換
最後程式碼的修改
增加 我方(Player1) 和 敵方(Player2) 的判斷
各自增加 一組 ButtonState 及 SumPlayer
紀錄 各自的 按鈕狀態 及 切換為正1狀態的統計陣列
最後程式碼
MainWindow.xaml.cs 版本3 (Final)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
namespace KinectV2_funnyApp
{
///
/// Interaction logic for MainWindow.xaml
///
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
int[] SumPlayer1 = new int[9];//0~8
//我們用Sum[1]~Sum[8]來對應連為一直線的累計數值狀態
int[] SumPlayer2 = new int[9];//0~8
int[] ButtonState1 = new int[10];
//ButtonState[1]~ButtonState[9]
int[] ButtonState2 = new int[10];
bool myTurn = true;
private void b1_Click(object sender, RoutedEventArgs e)
{
Button tmpButton = (Button)sender;//tmpButton中會有Uid
//ButtonState[1] = 1;
if (myTurn )
{
tmpButton.Content = "O";
ButtonState1[Convert.ToInt16(tmpButton.Uid)] = 1;
CheckSum();
myTurn = false;
}
else
{
tmpButton.Content = "X";
ButtonState2[Convert.ToInt16(tmpButton.Uid)] = 1;
CheckSum();
myTurn = true;
}
}
private void CheckSum()
{
SumPlayer1[1] = ButtonState1[1] + ButtonState1[2] + ButtonState1[3];
SumPlayer1[2] = ButtonState1[4] + ButtonState1[5] + ButtonState1[6];
SumPlayer1[3] = ButtonState1[7] + ButtonState1[8] + ButtonState1[9];
SumPlayer1[4] = ButtonState1[1] + ButtonState1[4] + ButtonState1[7];
SumPlayer1[5] = ButtonState1[2] + ButtonState1[5] + ButtonState1[8];
SumPlayer1[6] = ButtonState1[3] + ButtonState1[6] + ButtonState1[9];
SumPlayer1[7] = ButtonState1[1] + ButtonState1[5] + ButtonState1[9];
SumPlayer1[8] = ButtonState1[3] + ButtonState1[5] + ButtonState1[7];
SumPlayer2[1] = ButtonState2[1] + ButtonState2[2] + ButtonState2[3];
SumPlayer2[2] = ButtonState2[4] + ButtonState2[5] + ButtonState2[6];
SumPlayer2[3] = ButtonState2[7] + ButtonState2[8] + ButtonState2[9];
SumPlayer2[4] = ButtonState2[1] + ButtonState2[4] + ButtonState2[7];
SumPlayer2[5] = ButtonState2[2] + ButtonState2[5] + ButtonState2[8];
SumPlayer2[6] = ButtonState2[3] + ButtonState2[6] + ButtonState2[9];
SumPlayer2[7] = ButtonState2[1] + ButtonState2[5] + ButtonState2[9];
SumPlayer2[8] = ButtonState2[3] + ButtonState2[5] + ButtonState2[7];
if (myTurn)
if (SumPlayer1.Contains(3) == true)
MessageBox.Show("你(玩家1)贏了");
else
if (SumPlayer2.Contains(3) == true)
MessageBox.Show("對方(玩家2)贏了");
}
}
}
最後可成功對於 玩家1 及 玩家2 做判斷
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