LeetCode184. Department Highest Salary

Table: Employee

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| id           | int     |
| name         | varchar |
| salary       | int     |
| departmentId | int     |
+--------------+---------+
id is the primary key column for this table.
departmentId is a foreign key of the ID from the Department table.
Each row of this table indicates the ID, name, and salary of an employee. It also contains the ID of their department.

 Table: Department

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
+-------------+---------+
id is the primary key column for this table. It is guaranteed that department name is not NULL.
Each row of this table indicates the ID of a department and its name.

 Write an SQL query to find employees who have the highest salary in each of the departments.
Return the result table in any order.
The query result format is in the following example.

Input: 
Employee table:
+----+-------+--------+--------------+
| id | name  | salary | departmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Jim   | 90000  | 1            |
| 3  | Henry | 80000  | 2            |
| 4  | Sam   | 60000  | 2            |
| 5  | Max   | 90000  | 1            |
+----+-------+--------+--------------+
Department table:
+----+-------+
| id | name  |
+----+-------+
| 1  | IT    |
| 2  | Sales |
+----+-------+
Output: 
+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Jim      | 90000  |
| Sales      | Henry    | 80000  |
| IT         | Max      | 90000  |
+------------+----------+--------+
Explanation: Max and Jim both have the highest salary in the IT department and Henry has the highest salary in the Sales department.
with tmp as (
select D.id as did ,max(E.salary) as Salary from Employee E
join Department D
on E.departmentId = D.id
group by D.id)

select d.name as Department, e.name as Employee,e.salary as Salary from Employee e,
Department d,tmp 
where e.salary = tmp.Salary and e.departmentId = d.id and d.id=tmp.did




留言

這個網誌中的熱門文章

經得起原始碼資安弱點掃描的程式設計習慣培養(五)_Missing HSTS Header

經得起原始碼資安弱點掃描的程式設計習慣培養(三)_7.Cross Site Scripting(XSS)_Stored XSS_Reflected XSS All Clients

(2021年度)駕訓學科筆試準備題庫歸納分析_法規是非題