LeetCode946. Validate Stack Sequences(Medium)#Stack

給兩個陣列,一個陣列是紀錄推入 stack 的元素、一個陣列是從 stack 頂部彈出的元素。我們要做的事情就是驗證,在『依照順序推入 stack,並且在需要 pop 特定元素時 pop』這樣的規定中,這個 stack 是否能剛好完全清空。

Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
Output: true
Explanation: We might do the following sequence:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
Output: false
Explanation: 1 cannot be popped before 2.


可使用 stack 來依序儲存 pushed 的元素,然後在遇到 popped 的元素跟 stack 頂部相同時彈出。
要注意的是,可能會連續遇到好幾次的 popped 的元素跟 stack 頂部相同,所以需用 while 來解,直到元素不匹配時才停止。

ans1.

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
class Solution {
public:
    bool validateStackSequences(vector<int>& pushed, vector<int>& popped) {
        int pop_i = 0;
        stack<int> st;

        for (int i=0; i<pushed.size(); ++i) {
            st.push(pushed[i]);

            while (!st.empty() && popped[pop_i] == st.top()) {
                st.pop();
                ++pop_i;
            }
        }

        return st.empty();
    }
};








Ref:
https://www.algomooc.com/1104.html
https://medium.com/@ChYuan/leetcode-946-validate-stack-sequences-%E5%BF%83%E5%BE%97-medium-c8e3f10b02d2
https://blog.csdn.net/qq_17550379/article/details/84990454
https://blog.csdn.net/myRealization/article/details/111027387
https://clay-atlas.com/blog/2023/04/13/leetcode-946-validate-stack-sequences/
https://github.com/keineahnung2345/leetcode-cpp-practices/blob/master/946.%20Validate%20Stack%20Sequences.cpp

留言

這個網誌中的熱門文章

經得起原始碼資安弱點掃描的程式設計習慣培養(五)_Missing HSTS Header

經得起原始碼資安弱點掃描的程式設計習慣培養(三)_7.Cross Site Scripting(XSS)_Stored XSS_Reflected XSS All Clients

(2021年度)駕訓學科筆試準備題庫歸納分析_法規是非題